Base | Representation |
---|---|
bin | 1011111010110101110010… |
… | …0100010110011110110001 |
3 | 1201101212120201002002000211 |
4 | 2332231130210112132301 |
5 | 3204210030023100413 |
6 | 43512325514144121 |
7 | 2521561315064611 |
oct | 276553444263661 |
9 | 51355521062024 |
10 | 13105498253233 |
11 | 41a3013116931 |
12 | 1577b24a22041 |
13 | 740ac6619729 |
14 | 3344493a6a41 |
15 | 17ad8644883d |
hex | beb5c9167b1 |
13105498253233 has 2 divisors, whose sum is σ = 13105498253234. Its totient is φ = 13105498253232.
The previous prime is 13105498253213. The next prime is 13105498253251. The reversal of 13105498253233 is 33235289450131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12389076515344 + 716421737889 = 3519812^2 + 846417^2 .
It is a cyclic number.
It is not a de Polignac number, because 13105498253233 - 217 = 13105498122161 is a prime.
It is not a weakly prime, because it can be changed into another prime (13105498253203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552749126616 + 6552749126617.
It is an arithmetic number, because the mean of its divisors is an integer number (6552749126617).
Almost surely, 213105498253233 is an apocalyptic number.
It is an amenable number.
13105498253233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105498253233 is an equidigital number, since it uses as much as digits as its factorization.
13105498253233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 49.
The spelling of 13105498253233 in words is "thirteen trillion, one hundred five billion, four hundred ninety-eight million, two hundred fifty-three thousand, two hundred thirty-three".
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