13105654431 has 4 divisors (see below), whose sum is σ = 17474205912. Its totient is φ = 8737102952.

The previous prime is 13105654421. The next prime is 13105654543. The reversal of 13105654431 is 13445650131.

It is a happy number.

13105654431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105654431 - 2⁹ = 13105653919 is a prime.

It is a super-2 number, since 2×13105654431² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13105654392 and 13105654401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105654411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2184275736 + ... + 2184275741.

It is an arithmetic number, because the mean of its divisors is an integer number (4368551478).

Almost surely, 2^13105654431 is an apocalyptic number.

13105654431 is a deficient number, since it is larger than the sum of its proper divisors (4368551481).

13105654431 is an equidigital number, since it uses as much as digits as its factorization.

13105654431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4368551480.

The product of its (nonzero) digits is 21600, while the sum is 33.

The spelling of 13105654431 in words is "thirteen billion, one hundred five million, six hundred fifty-four thousand, four hundred thirty-one".