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13107148044499 is a prime number
BaseRepresentation
bin1011111010111011111011…
…1001110011100011010011
31201102000211200110011012001
42332232332321303203103
53204221414344410444
643513201331014431
72521650230062645
oct276567671634323
951360750404161
1013107148044499
1141a378a406493
12157830543a417
13740cca366892
1433456453c895
1517ae311d08d4
hexbebbee738d3

13107148044499 has 2 divisors, whose sum is σ = 13107148044500. Its totient is φ = 13107148044498.

The previous prime is 13107148044479. The next prime is 13107148044587. The reversal of 13107148044499 is 99444084170131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13107148044499 - 217 = 13107147913427 is a prime.

It is a super-2 number, since 2×131071480444992 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13107148044479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6553574022249 + 6553574022250.

It is an arithmetic number, because the mean of its divisors is an integer number (6553574022250).

Almost surely, 213107148044499 is an apocalyptic number.

13107148044499 is a deficient number, since it is larger than the sum of its proper divisors (1).

13107148044499 is an equidigital number, since it uses as much as digits as its factorization.

13107148044499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3483648, while the sum is 55.

The spelling of 13107148044499 in words is "thirteen trillion, one hundred seven billion, one hundred forty-eight million, forty-four thousand, four hundred ninety-nine".