1310987367659 has 2 divisors, whose sum is σ = 1310987367660. Its totient is φ = 1310987367658.

The previous prime is 1310987367649. The next prime is 1310987367671. The reversal of 1310987367659 is 9567637890131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310987367659 is a prime.

It is a super-2 number, since 2×1310987367659² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310987367595 and 1310987367604.

It is not a weakly prime, because it can be changed into another prime (1310987367649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655493683829 + 655493683830.

It is an arithmetic number, because the mean of its divisors is an integer number (655493683830).

Almost surely, 2^{1310987367659} is an apocalyptic number.

1310987367659 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310987367659 is an equidigital number, since it uses as much as digits as its factorization.

1310987367659 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51438240, while the sum is 65.

The spelling of 1310987367659 in words is "one trillion, three hundred ten billion, nine hundred eighty-seven million, three hundred sixty-seven thousand, six hundred fifty-nine".