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131099539 is a prime number
BaseRepresentation
bin1111101000001…
…10101110010011
3100010200112202111
413310012232103
5232030141124
621001530151
73151220254
oct764065623
9303615674
10131099539
116800302a
1237aa3957
13212120bc
14135a8b2b
15b799494
hex7d06b93

131099539 has 2 divisors, whose sum is σ = 131099540. Its totient is φ = 131099538.

The previous prime is 131099519. The next prime is 131099557. The reversal of 131099539 is 935990131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131099539 - 219 = 130575251 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131099519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65549769 + 65549770.

It is an arithmetic number, because the mean of its divisors is an integer number (65549770).

Almost surely, 2131099539 is an apocalyptic number.

131099539 is a deficient number, since it is larger than the sum of its proper divisors (1).

131099539 is an equidigital number, since it uses as much as digits as its factorization.

131099539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32805, while the sum is 40.

The square root of 131099539 is about 11449.8706979599. The cubic root of 131099539 is about 508.0039098527.

The spelling of 131099539 in words is "one hundred thirty-one million, ninety-nine thousand, five hundred thirty-nine".