Base | Representation |
---|---|
bin | 1011111011000110100100… |
… | …0101000110101001001011 |
3 | 1201102022012122210200022201 |
4 | 2332301221011012221023 |
5 | 3204243241300224003 |
6 | 43514352521301031 |
7 | 2522111045661100 |
oct | 276615105065113 |
9 | 51368178720281 |
10 | 13110003133003 |
11 | 41a4a14a9a767 |
12 | 1578981634777 |
13 | 741363a1136a |
14 | 3347557c2aa7 |
15 | 17b04bb9cb1d |
hex | bec69146a4b |
13110003133003 has 24 divisors (see below), whose sum is σ = 15291428486400. Its totient is φ = 11206943789328.
The previous prime is 13110003132997. The next prime is 13110003133027. The reversal of 13110003133003 is 30033130001131.
It is a happy number.
13110003133003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13110003133003 - 213 = 13110003124811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110003133103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 52771626 + ... + 53019472.
It is an arithmetic number, because the mean of its divisors is an integer number (637142853600).
Almost surely, 213110003133003 is an apocalyptic number.
13110003133003 is a deficient number, since it is larger than the sum of its proper divisors (2181425353397).
13110003133003 is a wasteful number, since it uses less digits than its factorization.
13110003133003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 250759 (or 250752 counting only the distinct ones).
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 13110003133003 its reverse (30033130001131), we get a palindrome (43143133134134).
The spelling of 13110003133003 in words is "thirteen trillion, one hundred ten billion, three million, one hundred thirty-three thousand, three".
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