Base | Representation |
---|---|
bin | 111101000011000110… |
… | …0000010110110000001 |
3 | 110112101121101110021222 |
4 | 1322012030002312001 |
5 | 4121443140320301 |
6 | 140120542524425 |
7 | 12320534234501 |
oct | 1720614026601 |
9 | 415347343258 |
10 | 131100323201 |
11 | 50665795251 |
12 | 214a9296715 |
13 | c493b39653 |
14 | 64b968da01 |
15 | 362476031b |
hex | 1e86302d81 |
131100323201 has 2 divisors, whose sum is σ = 131100323202. Its totient is φ = 131100323200.
The previous prime is 131100323191. The next prime is 131100323239. The reversal of 131100323201 is 102323001131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130303672576 + 796650625 = 360976^2 + 28225^2 .
It is a cyclic number.
It is not a de Polignac number, because 131100323201 - 214 = 131100306817 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 131100323201.
It is not a weakly prime, because it can be changed into another prime (131100623201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550161600 + 65550161601.
It is an arithmetic number, because the mean of its divisors is an integer number (65550161601).
Almost surely, 2131100323201 is an apocalyptic number.
It is an amenable number.
131100323201 is a deficient number, since it is larger than the sum of its proper divisors (1).
131100323201 is an equidigital number, since it uses as much as digits as its factorization.
131100323201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 131100323201 its reverse (102323001131), we get a palindrome (233423324332).
The spelling of 131100323201 in words is "one hundred thirty-one billion, one hundred million, three hundred twenty-three thousand, two hundred one".
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