Base | Representation |
---|---|
bin | 1011111011000110101011… |
… | …0111000010011001101010 |
3 | 1201102022021202000002012100 |
4 | 2332301222313002121222 |
5 | 3204243321422000132 |
6 | 43514355505354230 |
7 | 2522111560564026 |
oct | 276615267023152 |
9 | 51368252002170 |
10 | 13110033000042 |
11 | 41a4a2a93a270 |
12 | 157898b638976 |
13 | 741369c6a974 |
14 | 334759759386 |
15 | 17b04e5ec37c |
hex | bec6adc266a |
13110033000042 has 48 divisors (see below), whose sum is σ = 31195319594400. Its totient is φ = 3946074597600.
The previous prime is 13110032999993. The next prime is 13110033000083. The reversal of 13110033000042 is 24000033001131.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13110032999979 and 13110033000024.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 222159384 + ... + 222218387.
It is an arithmetic number, because the mean of its divisors is an integer number (649902491550).
Almost surely, 213110033000042 is an apocalyptic number.
13110033000042 is an abundant number, since it is smaller than the sum of its proper divisors (18085286594358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110033000042 is a wasteful number, since it uses less digits than its factorization.
13110033000042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444377939 (or 444377936 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13110033000042 its reverse (24000033001131), we get a palindrome (37110066001173).
The spelling of 13110033000042 in words is "thirteen trillion, one hundred ten billion, thirty-three million, forty-two", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.138 sec. • engine limits •