13110040000313 has 2 divisors, whose sum is σ = 13110040000314. Its totient is φ = 13110040000312.

The previous prime is 13110040000279. The next prime is 13110040000319. The reversal of 13110040000313 is 31300004001131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9968751672889 + 3141288327424 = 3157333^2 + 1772368^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110040000313 - 2²⁴ = 13110023223097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110040000291 and 13110040000300.

It is not a weakly prime, because it can be changed into another prime (13110040000319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555020000156 + 6555020000157.

It is an arithmetic number, because the mean of its divisors is an integer number (6555020000157).

Almost surely, 2^{13110040000313} is an apocalyptic number.

It is an amenable number.

13110040000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110040000313 is an equidigital number, since it uses as much as digits as its factorization.

13110040000313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13110040000313 its reverse (31300004001131), we get a palindrome (44410044001444).

The spelling of 13110040000313 in words is "thirteen trillion, one hundred ten billion, forty million, three hundred thirteen", and thus it is an aban number.