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13110044198353 is a prime number
BaseRepresentation
bin1011111011000110101110…
…0001110000010111010001
31201102022022112002000101121
42332301223201300113101
53204243332303321403
643514400545402241
72522112055014124
oct276615341602721
951368275060347
1013110044198353
1141a4a36198773
121578993339381
1374136c38ba9b
1433475b0323bb
1517b0505b03bd
hexbec6b8705d1

13110044198353 has 2 divisors, whose sum is σ = 13110044198354. Its totient is φ = 13110044198352.

The previous prime is 13110044198327. The next prime is 13110044198491. The reversal of 13110044198353 is 35389144001131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13092362645569 + 17681552784 = 3618337^2 + 132972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110044198353 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110044198753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555022099176 + 6555022099177.

It is an arithmetic number, because the mean of its divisors is an integer number (6555022099177).

Almost surely, 213110044198353 is an apocalyptic number.

It is an amenable number.

13110044198353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110044198353 is an equidigital number, since it uses as much as digits as its factorization.

13110044198353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 43.

Adding to 13110044198353 its reverse (35389144001131), we get a palindrome (48499188199484).

The spelling of 13110044198353 in words is "thirteen trillion, one hundred ten billion, forty-four million, one hundred ninety-eight thousand, three hundred fifty-three".