131101000421 has 4 divisors (see below), whose sum is σ = 131102878272. Its totient is φ = 131099122572.

The previous prime is 131101000411. The next prime is 131101000427. The reversal of 131101000421 is 124000101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 124000101131 = 103 ⋅1203884477.

It is a cyclic number.

It is not a de Polignac number, because 131101000421 - 2²² = 131096806117 is a prime.

It is a super-2 number, since 2×131101000421² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131101000396 and 131101000405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131101000427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 829991 + ... + 975236.

It is an arithmetic number, because the mean of its divisors is an integer number (32775719568).

Almost surely, 2^131101000421 is an apocalyptic number.

It is an amenable number.

131101000421 is a deficient number, since it is larger than the sum of its proper divisors (1877851).

131101000421 is an equidigital number, since it uses as much as digits as its factorization.

131101000421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1877850.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 131101000421 its reverse (124000101131), we get a palindrome (255101101552).

The spelling of 131101000421 in words is "one hundred thirty-one billion, one hundred one million, four hundred twenty-one", and thus it is an aban number.