Base | Representation |
---|---|
bin | 10011000100111110010… |
… | …010010100001100110100 |
3 | 11122022221112122010002121 |
4 | 103010332102110030310 |
5 | 132434422030422004 |
6 | 2442134130245324 |
7 | 163501023152515 |
oct | 23047622241464 |
9 | 4568845563077 |
10 | 1311010014004 |
11 | 465aa5a7a719 |
12 | 1920ba726844 |
13 | 96821119b22 |
14 | 4764b904a0c |
15 | 241807e1854 |
hex | 1313e494334 |
1311010014004 has 12 divisors (see below), whose sum is σ = 2294347701184. Its totient is φ = 655482099384.
The previous prime is 1311010013981. The next prime is 1311010014047. The reversal of 1311010014004 is 4004100101131.
It is a super-2 number, since 2×13110100140042 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5597814 + ... + 5827309.
Almost surely, 21311010014004 is an apocalyptic number.
It is an amenable number.
1311010014004 is a deficient number, since it is larger than the sum of its proper divisors (983337687180).
1311010014004 is a wasteful number, since it uses less digits than its factorization.
1311010014004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11453814 (or 11453812 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1311010014004 its reverse (4004100101131), we get a palindrome (5315110115135).
The spelling of 1311010014004 in words is "one trillion, three hundred eleven billion, ten million, fourteen thousand, four".
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