Base | Representation |
---|---|
bin | 1011111011000110111011… |
… | …1000001001110100000010 |
3 | 1201102022110102211102111022 |
4 | 2332301232320021310002 |
5 | 3204243441200321120 |
6 | 43514410314145442 |
7 | 2522113336515335 |
oct | 276615670116402 |
9 | 51368412742438 |
10 | 13110100401410 |
11 | 41a4a64995981 |
12 | 15789aa122282 |
13 | 74137ac0972c |
14 | 3347646a261c |
15 | 17b0554b3025 |
hex | bec6ee09d02 |
13110100401410 has 8 divisors (see below), whose sum is σ = 23598180722556. Its totient is φ = 5244040160560.
The previous prime is 13110100401397. The next prime is 13110100401427. The reversal of 13110100401410 is 1410400101131.
13110100401410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 10977738213289 + 2132362188121 = 3313267^2 + 1460261^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655505020061 + ... + 655505020080.
Almost surely, 213110100401410 is an apocalyptic number.
13110100401410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13110100401410 is a deficient number, since it is larger than the sum of its proper divisors (10488080321146).
13110100401410 is a wasteful number, since it uses less digits than its factorization.
13110100401410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1311010040148.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 13110100401410 its reverse (1410400101131), we get a palindrome (14520500502541).
The spelling of 13110100401410 in words is "thirteen trillion, one hundred ten billion, one hundred million, four hundred one thousand, four hundred ten".
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