13110101020221 has 4 divisors (see below), whose sum is σ = 17480134693632. Its totient is φ = 8740067346812.

The previous prime is 13110101020193. The next prime is 13110101020327. The reversal of 13110101020221 is 12202010101131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110101020221 - 2²⁹ = 13109564149309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13110101020221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110101020421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185016836701 + ... + 2185016836706.

It is an arithmetic number, because the mean of its divisors is an integer number (4370033673408).

Almost surely, 2^{13110101020221} is an apocalyptic number.

It is an amenable number.

13110101020221 is a deficient number, since it is larger than the sum of its proper divisors (4370033673411).

13110101020221 is an equidigital number, since it uses as much as digits as its factorization.

13110101020221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4370033673410.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13110101020221 its reverse (12202010101131), we get a palindrome (25312111121352).

The spelling of 13110101020221 in words is "thirteen trillion, one hundred ten billion, one hundred one million, twenty thousand, two hundred twenty-one".