Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0100100001100011101001 |
3 | 1201102022111020201101000222 |
4 | 2332301233210201203221 |
5 | 3204244002140024001 |
6 | 43514411411335425 |
7 | 2522113540421564 |
oct | 276615744414351 |
9 | 51368436641028 |
10 | 13110112033001 |
11 | 41a4a7050a965 |
12 | 15789b1bb1575 |
13 | 74138044cb29 |
14 | 33476604d4db |
15 | 17b05650e61b |
hex | bec6f9218e9 |
13110112033001 has 2 divisors, whose sum is σ = 13110112033002. Its totient is φ = 13110112033000.
The previous prime is 13110112032989. The next prime is 13110112033009. The reversal of 13110112033001 is 10033021101131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9136564155625 + 3973547877376 = 3022675^2 + 1993376^2 .
It is a cyclic number.
It is not a de Polignac number, because 13110112033001 - 218 = 13110111770857 is a prime.
It is a super-2 number, since 2×131101120330012 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13110112033009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056016500 + 6555056016501.
It is an arithmetic number, because the mean of its divisors is an integer number (6555056016501).
Almost surely, 213110112033001 is an apocalyptic number.
It is an amenable number.
13110112033001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110112033001 is an equidigital number, since it uses as much as digits as its factorization.
13110112033001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13110112033001 its reverse (10033021101131), we get a palindrome (23143133134132).
The spelling of 13110112033001 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, thirty-three thousand, one".
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