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13110130023 = 317257061373
BaseRepresentation
bin11000011010110110…
…01011010101100111
31020211200000121110020
430031123023111213
5203322143130043
610004523330223
7642611160264
oct141533132547
936750017406
1013110130023
115618365801
12265a680973
13130c1512b3
148c523626b
1551ae57e83
hex30d6cb567

13110130023 has 8 divisors (see below), whose sum is σ = 18508418928. Its totient is φ = 8225963904.

The previous prime is 13110130013. The next prime is 13110130063. The reversal of 13110130023 is 32003101131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13110130023 - 29 = 13110129511 is a prime.

It is a super-4 number, since 4×131101300234 (a number of 42 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110129984 and 13110130011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110130013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128530636 + ... + 128530737.

It is an arithmetic number, because the mean of its divisors is an integer number (2313552366).

Almost surely, 213110130023 is an apocalyptic number.

13110130023 is a deficient number, since it is larger than the sum of its proper divisors (5398288905).

13110130023 is a wasteful number, since it uses less digits than its factorization.

13110130023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257061393.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13110130023 its reverse (32003101131), we get a palindrome (45113231154).

The spelling of 13110130023 in words is "thirteen billion, one hundred ten million, one hundred thirty thousand, twenty-three".

Divisors: 1 3 17 51 257061373 771184119 4370043341 13110130023