Base | Representation |
---|---|
bin | 11000011010110110… |
… | …01011010110001111 |
3 | 1020211200000121111201 |
4 | 30031123023112033 |
5 | 203322143130223 |
6 | 10004523330331 |
7 | 642611160352 |
oct | 141533132617 |
9 | 36750017451 |
10 | 13110130063 |
11 | 5618365838 |
12 | 265a6809a7 |
13 | 130c151314 |
14 | 8c5236299 |
15 | 51ae57ead |
hex | 30d6cb58f |
13110130063 has 2 divisors, whose sum is σ = 13110130064. Its totient is φ = 13110130062.
The previous prime is 13110130013. The next prime is 13110130073. The reversal of 13110130063 is 36003101131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13110130063 - 217 = 13109998991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13110130063.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110130013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555065031 + 6555065032.
It is an arithmetic number, because the mean of its divisors is an integer number (6555065032).
Almost surely, 213110130063 is an apocalyptic number.
13110130063 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110130063 is an equidigital number, since it uses as much as digits as its factorization.
13110130063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13110130063 its reverse (36003101131), we get a palindrome (49113231194).
The spelling of 13110130063 in words is "thirteen billion, one hundred ten million, one hundred thirty thousand, sixty-three".
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