1311013109993 has 2 divisors, whose sum is σ = 1311013109994. Its totient is φ = 1311013109992.

The previous prime is 1311013109957. The next prime is 1311013110013. The reversal of 1311013109993 is 3999013101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1030799570089 + 280213539904 = 1015283^2 + 529352^2 .

It is an emirp because it is prime and its reverse (3999013101131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311013109993 - 2²⁸ = 1310744674537 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311013109993.

It is not a weakly prime, because it can be changed into another prime (1311013103993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655506554996 + 655506554997.

It is an arithmetic number, because the mean of its divisors is an integer number (655506554997).

Almost surely, 2^{1311013109993} is an apocalyptic number.

It is an amenable number.

1311013109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311013109993 is an equidigital number, since it uses as much as digits as its factorization.

1311013109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19683, while the sum is 41.

The spelling of 1311013109993 in words is "one trillion, three hundred eleven billion, thirteen million, one hundred nine thousand, nine hundred ninety-three".