Base | Representation |
---|---|
bin | 11101110011110001100111… |
… | …000101010111011111111010 |
3 | 122012012011101210100002022120 |
4 | 131303301213011113133322 |
5 | 114140430441132001242 |
6 | 1142455035543102110 |
7 | 36420520464400305 |
oct | 3563614705273772 |
9 | 565164353302276 |
10 | 131101311203322 |
11 | 38855832408729 |
12 | 1285438ba41936 |
13 | 581ca53bbb8c5 |
14 | 24534a1861b3c |
15 | 10253a51ee1ec |
hex | 773c671577fa |
131101311203322 has 16 divisors (see below), whose sum is σ = 262205997933600. Its totient is φ = 43699874479952.
The previous prime is 131101311203311. The next prime is 131101311203323. The reversal of 131101311203322 is 223302113101131.
It is a junction number, because it is equal to n+sod(n) for n = 131101311203292 and 131101311203301.
It is not an unprimeable number, because it can be changed into a prime (131101311203323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 140141913 + ... + 141074300.
It is an arithmetic number, because the mean of its divisors is an integer number (16387874870850).
Almost surely, 2131101311203322 is an apocalyptic number.
131101311203322 is an abundant number, since it is smaller than the sum of its proper divisors (131104686730278).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131101311203322 is a wasteful number, since it uses less digits than its factorization.
131101311203322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281293917.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 131101311203322 its reverse (223302113101131), we get a palindrome (354403424304453).
The spelling of 131101311203322 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred eleven million, two hundred three thousand, three hundred twenty-two".
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