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131101311541441 is a prime number
BaseRepresentation
bin11101110011110001100111…
…000110101010000011000001
3122012012011101210222021010111
4131303301213012222003001
5114140430441223311231
61142455035554231321
736420520500306133
oct3563614706520301
9565164353867114
10131101311541441
113885583261976a
121285438bb85541
13581ca53ca9787
1424534a190d053
1510253a52694b1
hex773c671aa0c1

131101311541441 has 2 divisors, whose sum is σ = 131101311541442. Its totient is φ = 131101311541440.

The previous prime is 131101311541423. The next prime is 131101311541537. The reversal of 131101311541441 is 144145113101131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129770737756416 + 1330573785025 = 11391696^2 + 1153505^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101311541441 - 27 = 131101311541313 is a prime.

It is not a weakly prime, because it can be changed into another prime (131101311641441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550655770720 + 65550655770721.

It is an arithmetic number, because the mean of its divisors is an integer number (65550655770721).

Almost surely, 2131101311541441 is an apocalyptic number.

It is an amenable number.

131101311541441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101311541441 is an equidigital number, since it uses as much as digits as its factorization.

131101311541441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 31.

Adding to 131101311541441 its reverse (144145113101131), we get a palindrome (275246424642572).

The spelling of 131101311541441 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred eleven million, five hundred forty-one thousand, four hundred forty-one".