13110141040331 has 2 divisors, whose sum is σ = 13110141040332. Its totient is φ = 13110141040330.

The previous prime is 13110141040319. The next prime is 13110141040349. The reversal of 13110141040331 is 13304014101131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110141040331 is a prime.

It is a super-2 number, since 2×13110141040331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110141040297 and 13110141040306.

It is not a weakly prime, because it can be changed into another prime (13110141040231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555070520165 + 6555070520166.

It is an arithmetic number, because the mean of its divisors is an integer number (6555070520166).

Almost surely, 2^{13110141040331} is an apocalyptic number.

13110141040331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110141040331 is an equidigital number, since it uses as much as digits as its factorization.

13110141040331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13110141040331 its reverse (13304014101131), we get a palindrome (26414155141462).

The spelling of 13110141040331 in words is "thirteen trillion, one hundred ten billion, one hundred forty-one million, forty thousand, three hundred thirty-one".