Base | Representation |
---|---|
bin | 11101110011110001110010… |
… | …100110000110100111101010 |
3 | 122012012011220020202011020021 |
4 | 131303301302212012213222 |
5 | 114140431340102144224 |
6 | 1142455111042351054 |
7 | 36420525331105363 |
oct | 3563616246064752 |
9 | 565164806664207 |
10 | 131101504334314 |
11 | 38855921429918 |
12 | 1285442465b48a |
13 | 581ca84c0c4b7 |
14 | 24534bd376b6a |
15 | 10253b714d1e4 |
hex | 773c729869ea |
131101504334314 has 4 divisors (see below), whose sum is σ = 196652256501474. Its totient is φ = 65550752167156.
The previous prime is 131101504334309. The next prime is 131101504334369. The reversal of 131101504334314 is 413433405101131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 128224664318689 + 2876840015625 = 11323633^2 + 1696125^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 131101504334314.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32775376083577 + ... + 32775376083580.
Almost surely, 2131101504334314 is an apocalyptic number.
131101504334314 is a deficient number, since it is larger than the sum of its proper divisors (65550752167160).
131101504334314 is an equidigital number, since it uses as much as digits as its factorization.
131101504334314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65550752167159.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 131101504334314 its reverse (413433405101131), we get a palindrome (544534909435445).
The spelling of 131101504334314 in words is "one hundred thirty-one trillion, one hundred one billion, five hundred four million, three hundred thirty-four thousand, three hundred fourteen".
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