13110204113 has 2 divisors, whose sum is σ = 13110204114. Its totient is φ = 13110204112.

The previous prime is 13110204097. The next prime is 13110204181. The reversal of 13110204113 is 31140201131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13107273169 + 2930944 = 114487^2 + 1712^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110204113 - 2⁴ = 13110204097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110204091 and 13110204100.

It is not a weakly prime, because it can be changed into another prime (13110204013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555102056 + 6555102057.

It is an arithmetic number, because the mean of its divisors is an integer number (6555102057).

Almost surely, 2^13110204113 is an apocalyptic number.

It is an amenable number.

13110204113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110204113 is an equidigital number, since it uses as much as digits as its factorization.

13110204113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110204113 its reverse (31140201131), we get a palindrome (44250405244).

The spelling of 13110204113 in words is "thirteen billion, one hundred ten million, two hundred four thousand, one hundred thirteen".