Base | Representation |
---|---|
bin | 11101110011110010010110… |
… | …010110001100000111110011 |
3 | 122012012020110001101120010201 |
4 | 131303302112112030013303 |
5 | 114140434102130023243 |
6 | 1142455250350340031 |
7 | 36420546233304646 |
oct | 3563622626140763 |
9 | 565166401346121 |
10 | 131102104142323 |
11 | 388560a9a66516 |
12 | 128545714ba617 |
13 | 581cb4c26b892 |
14 | 2453538cada5d |
15 | 10253eeb2e04d |
hex | 773c9658c1f3 |
131102104142323 has 2 divisors, whose sum is σ = 131102104142324. Its totient is φ = 131102104142322.
The previous prime is 131102104142309. The next prime is 131102104142381. The reversal of 131102104142323 is 323241401201131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131102104142323 - 25 = 131102104142291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131102104142291 and 131102104142300.
It is not a weakly prime, because it can be changed into another prime (131102104542323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551052071161 + 65551052071162.
It is an arithmetic number, because the mean of its divisors is an integer number (65551052071162).
Almost surely, 2131102104142323 is an apocalyptic number.
131102104142323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131102104142323 is an equidigital number, since it uses as much as digits as its factorization.
131102104142323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 131102104142323 its reverse (323241401201131), we get a palindrome (454343505343454).
The spelling of 131102104142323 in words is "one hundred thirty-one trillion, one hundred two billion, one hundred four million, one hundred forty-two thousand, three hundred twenty-three".
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