Base | Representation |
---|---|
bin | 1011111011000111010101… |
… | …1100000010010100100011 |
3 | 1201102022202002221112212022 |
4 | 2332301311130002110203 |
5 | 3204244202340034303 |
6 | 43514425245252055 |
7 | 2522116144220456 |
oct | 276616534022443 |
9 | 51368662845768 |
10 | 13110210471203 |
11 | 41a5011034a4a |
12 | 1578a1ab6402b |
13 | 7413979677a1 |
14 | 33477515549d |
15 | 17b05eea6438 |
hex | bec75702523 |
13110210471203 has 2 divisors, whose sum is σ = 13110210471204. Its totient is φ = 13110210471202.
The previous prime is 13110210471161. The next prime is 13110210471257. The reversal of 13110210471203 is 30217401201131.
13110210471203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (30217401201131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13110210471203 - 216 = 13110210405667 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110210471103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555105235601 + 6555105235602.
It is an arithmetic number, because the mean of its divisors is an integer number (6555105235602).
Almost surely, 213110210471203 is an apocalyptic number.
13110210471203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110210471203 is an equidigital number, since it uses as much as digits as its factorization.
13110210471203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 13110210471203 its reverse (30217401201131), we get a palindrome (43327611672334).
The spelling of 13110210471203 in words is "thirteen trillion, one hundred ten billion, two hundred ten million, four hundred seventy-one thousand, two hundred three".
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