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1311021536138 = 2679783742807
BaseRepresentation
bin10011000100111110111…
…110010001001110001010
311122022222100022111111022
4103010332332101032022
5132434433003124023
62442135221232442
7163501223121656
oct23047676211612
94568870274438
101311021536138
1146600152a446
12192102562722
1396823622462
144764d263a66
152418181a7c8
hex1313ef9138a

1311021536138 has 8 divisors (see below), whose sum is σ = 1995883532832. Its totient is φ = 645727025196.

The previous prime is 1311021536137. The next prime is 1311021536141. The reversal of 1311021536138 is 8316351201131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1311021536098 and 1311021536107.

It is not an unprimeable number, because it can be changed into a prime (1311021536137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4891871270 + ... + 4891871537.

It is an arithmetic number, because the mean of its divisors is an integer number (249485441604).

Almost surely, 21311021536138 is an apocalyptic number.

1311021536138 is a deficient number, since it is larger than the sum of its proper divisors (684861996694).

1311021536138 is an equidigital number, since it uses as much as digits as its factorization.

1311021536138 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9783742876.

The product of its (nonzero) digits is 12960, while the sum is 35.

Adding to 1311021536138 its reverse (8316351201131), we get a palindrome (9627372737269).

The spelling of 1311021536138 in words is "one trillion, three hundred eleven billion, twenty-one million, five hundred thirty-six thousand, one hundred thirty-eight".

Divisors: 1 2 67 134 9783742807 19567485614 655510768069 1311021536138