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1311021536141 is a prime number
BaseRepresentation
bin10011000100111110111…
…110010001001110001101
311122022222100022111111102
4103010332332101032031
5132434433003124031
62442135221232445
7163501223121662
oct23047676211615
94568870274442
101311021536141
1146600152a449
12192102562725
1396823622465
144764d263a69
152418181a7cb
hex1313ef9138d

1311021536141 has 2 divisors, whose sum is σ = 1311021536142. Its totient is φ = 1311021536140.

The previous prime is 1311021536137. The next prime is 1311021536183. The reversal of 1311021536141 is 1416351201131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1226381271241 + 84640264900 = 1107421^2 + 290930^2 .

It is an emirp because it is prime and its reverse (1416351201131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311021536141 - 22 = 1311021536137 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311021532141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655510768070 + 655510768071.

It is an arithmetic number, because the mean of its divisors is an integer number (655510768071).

Almost surely, 21311021536141 is an apocalyptic number.

It is an amenable number.

1311021536141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311021536141 is an equidigital number, since it uses as much as digits as its factorization.

1311021536141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 29.

Adding to 1311021536141 its reverse (1416351201131), we get a palindrome (2727372737272).

The spelling of 1311021536141 in words is "one trillion, three hundred eleven billion, twenty-one million, five hundred thirty-six thousand, one hundred forty-one".