Base | Representation |
---|---|
bin | 10011000100111111000… |
… | …000011101111010110010 |
3 | 11122022222101101210000121 |
4 | 103010333000131322302 |
5 | 132434433130044214 |
6 | 2442135241440454 |
7 | 163501231042066 |
oct | 23047700357262 |
9 | 4568871353017 |
10 | 1311022112434 |
11 | 466001893421 |
12 | 1921027a012a |
13 | 96823794868 |
14 | 4764d373aa6 |
15 | 241818d1424 |
hex | 1313f01deb2 |
1311022112434 has 4 divisors (see below), whose sum is σ = 1966533168654. Its totient is φ = 655511056216.
The previous prime is 1311022112429. The next prime is 1311022112473. The reversal of 1311022112434 is 4342112201131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 824999807025 + 486022305409 = 908295^2 + 697153^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1311022112399 and 1311022112408.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327755528107 + ... + 327755528110.
Almost surely, 21311022112434 is an apocalyptic number.
1311022112434 is a deficient number, since it is larger than the sum of its proper divisors (655511056220).
1311022112434 is an equidigital number, since it uses as much as digits as its factorization.
1311022112434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655511056219.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1311022112434 its reverse (4342112201131), we get a palindrome (5653134313565).
The spelling of 1311022112434 in words is "one trillion, three hundred eleven billion, twenty-two million, one hundred twelve thousand, four hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •