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1311022112434 = 2655511056217
BaseRepresentation
bin10011000100111111000…
…000011101111010110010
311122022222101101210000121
4103010333000131322302
5132434433130044214
62442135241440454
7163501231042066
oct23047700357262
94568871353017
101311022112434
11466001893421
121921027a012a
1396823794868
144764d373aa6
15241818d1424
hex1313f01deb2

1311022112434 has 4 divisors (see below), whose sum is σ = 1966533168654. Its totient is φ = 655511056216.

The previous prime is 1311022112429. The next prime is 1311022112473. The reversal of 1311022112434 is 4342112201131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 824999807025 + 486022305409 = 908295^2 + 697153^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311022112399 and 1311022112408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327755528107 + ... + 327755528110.

Almost surely, 21311022112434 is an apocalyptic number.

1311022112434 is a deficient number, since it is larger than the sum of its proper divisors (655511056220).

1311022112434 is an equidigital number, since it uses as much as digits as its factorization.

1311022112434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655511056219.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1311022112434 its reverse (4342112201131), we get a palindrome (5653134313565).

The spelling of 1311022112434 in words is "one trillion, three hundred eleven billion, twenty-two million, one hundred twelve thousand, four hundred thirty-four".

Divisors: 1 2 655511056217 1311022112434