Search a number
-
+
13110223121 is a prime number
BaseRepresentation
bin11000011010110111…
…00010000100010001
31020211200012100011022
430031123202010101
5203322204114441
610004525325225
7642612025562
oct141533420421
936750170138
1013110223121
115618419746
12265a706815
13130c184798
148c525c169
1551ae7584b
hex30d6e2111

13110223121 has 2 divisors, whose sum is σ = 13110223122. Its totient is φ = 13110223120.

The previous prime is 13110223073. The next prime is 13110223127. The reversal of 13110223121 is 12132201131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10045050625 + 3065172496 = 100225^2 + 55364^2 .

It is an emirp because it is prime and its reverse (12132201131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110223121 is a prime.

It is a super-3 number, since 3×131102231213 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13110223121.

It is not a weakly prime, because it can be changed into another prime (13110223127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555111560 + 6555111561.

It is an arithmetic number, because the mean of its divisors is an integer number (6555111561).

Almost surely, 213110223121 is an apocalyptic number.

It is an amenable number.

13110223121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110223121 is an equidigital number, since it uses as much as digits as its factorization.

13110223121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13110223121 its reverse (12132201131), we get a palindrome (25242424252).

The spelling of 13110223121 in words is "thirteen billion, one hundred ten million, two hundred twenty-three thousand, one hundred twenty-one".