Base | Representation |
---|---|
bin | 11101110011110010100100… |
… | …011111011000100011000110 |
3 | 122012012021001120220012111101 |
4 | 131303302210133120203012 |
5 | 114140440043401333132 |
6 | 1142455330104330314 |
7 | 36420555144246043 |
oct | 3563624437304306 |
9 | 565167046805441 |
10 | 131102341433542 |
11 | 388562109a9966 |
12 | 12854618a7399a |
13 | 581cb8948179b |
14 | 245355c5dc1ca |
15 | 10254158a27e7 |
hex | 773ca47d88c6 |
131102341433542 has 8 divisors (see below), whose sum is σ = 196653928243032. Its totient is φ = 65551032019200.
The previous prime is 131102341433461. The next prime is 131102341433551. The reversal of 131102341433542 is 245334143201131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1311023414335423 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68163184 + ... + 70060147.
It is an arithmetic number, because the mean of its divisors is an integer number (24581741030379).
Almost surely, 2131102341433542 is an apocalyptic number.
131102341433542 is a deficient number, since it is larger than the sum of its proper divisors (65551586809490).
131102341433542 is a wasteful number, since it uses less digits than its factorization.
131102341433542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138697574.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 131102341433542 its reverse (245334143201131), we get a palindrome (376436484634673).
The spelling of 131102341433542 in words is "one hundred thirty-one trillion, one hundred two billion, three hundred forty-one million, four hundred thirty-three thousand, five hundred forty-two".
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