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131102341433542 = 2474241138223331
BaseRepresentation
bin11101110011110010100100…
…011111011000100011000110
3122012012021001120220012111101
4131303302210133120203012
5114140440043401333132
61142455330104330314
736420555144246043
oct3563624437304306
9565167046805441
10131102341433542
11388562109a9966
1212854618a7399a
13581cb8948179b
14245355c5dc1ca
1510254158a27e7
hex773ca47d88c6

131102341433542 has 8 divisors (see below), whose sum is σ = 196653928243032. Its totient is φ = 65551032019200.

The previous prime is 131102341433461. The next prime is 131102341433551. The reversal of 131102341433542 is 245334143201131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1311023414335423 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68163184 + ... + 70060147.

It is an arithmetic number, because the mean of its divisors is an integer number (24581741030379).

Almost surely, 2131102341433542 is an apocalyptic number.

131102341433542 is a deficient number, since it is larger than the sum of its proper divisors (65551586809490).

131102341433542 is a wasteful number, since it uses less digits than its factorization.

131102341433542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138697574.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 131102341433542 its reverse (245334143201131), we get a palindrome (376436484634673).

The spelling of 131102341433542 in words is "one hundred thirty-one trillion, one hundred two billion, three hundred forty-one million, four hundred thirty-three thousand, five hundred forty-two".

Divisors: 1 2 474241 948482 138223331 276446662 65551170716771 131102341433542