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13110300000 = 25325572081
BaseRepresentation
bin11000011010110111…
…10100110101100000
31020211200100020121200
430031123310311200
5203322214100000
610004531121200
7642612465660
oct141533646540
936750306550
1013110300000
115618471486
12265a743200
13130c1b0785
148c527c1a0
1551ae8d500
hex30d6f4d60

13110300000 has 432 divisors, whose sum is σ = 53282777184. Its totient is φ = 2995200000.

The previous prime is 13110299999. The next prime is 13110300001. The reversal of 13110300000 is 301131.

13110300000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13110299999) and next prime (13110300001).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110300001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 6298960 + ... + 6301040.

It is an arithmetic number, because the mean of its divisors is an integer number (123339762).

Almost surely, 213110300000 is an apocalyptic number.

13110300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26641388592).

13110300000 is an abundant number, since it is smaller than the sum of its proper divisors (40172477184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110300000 is an equidigital number, since it uses as much as digits as its factorization.

13110300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2129 (or 2098 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

Adding to 13110300000 its reverse (301131), we get a palindrome (13110601131).

The spelling of 13110300000 in words is "thirteen billion, one hundred ten million, three hundred thousand".