Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1000001011111010001 |
3 | 110112101210210200012202 |
4 | 1322012113001133101 |
5 | 4121444404414413 |
6 | 140121124332545 |
7 | 12320600552324 |
oct | 1720627013721 |
9 | 415353720182 |
10 | 131103201233 |
11 | 50667380594 |
12 | 214aa244155 |
13 | c494606624 |
14 | 64b9bdc7bb |
15 | 3624b2ce58 |
hex | 1e865c17d1 |
131103201233 has 2 divisors, whose sum is σ = 131103201234. Its totient is φ = 131103201232.
The previous prime is 131103201179. The next prime is 131103201259. The reversal of 131103201233 is 332102301131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128671429264 + 2431771969 = 358708^2 + 49313^2 .
It is an emirp because it is prime and its reverse (332102301131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131103201233 - 216 = 131103135697 is a prime.
It is not a weakly prime, because it can be changed into another prime (131103201283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551600616 + 65551600617.
It is an arithmetic number, because the mean of its divisors is an integer number (65551600617).
Almost surely, 2131103201233 is an apocalyptic number.
It is an amenable number.
131103201233 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103201233 is an equidigital number, since it uses as much as digits as its factorization.
131103201233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131103201233 its reverse (332102301131), we get a palindrome (463205502364).
The spelling of 131103201233 in words is "one hundred thirty-one billion, one hundred three million, two hundred one thousand, two hundred thirty-three".
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