13110332540053 has 4 divisors (see below), whose sum is σ = 14983237188640. Its totient is φ = 11237427891468.

The previous prime is 13110332539987. The next prime is 13110332540101. The reversal of 13110332540053 is 35004523301131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13110332540053 - 2²⁹ = 13109795669141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110332539997 and 13110332540024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110332540353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936452324283 + ... + 936452324296.

It is an arithmetic number, because the mean of its divisors is an integer number (3745809297160).

Almost surely, 2^{13110332540053} is an apocalyptic number.

It is an amenable number.

13110332540053 is a deficient number, since it is larger than the sum of its proper divisors (1872904648587).

13110332540053 is an equidigital number, since it uses as much as digits as its factorization.

13110332540053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1872904648586.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 13110332540053 its reverse (35004523301131), we get a palindrome (48114855841184).

The spelling of 13110332540053 in words is "thirteen trillion, one hundred ten billion, three hundred thirty-two million, five hundred forty thousand, fifty-three".