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131103411343520 = 25571138512763311
BaseRepresentation
bin11101110011110011100100…
…010000110001000010100000
3122012012100211011010021001212
4131303303210100301002200
5114140444241300443040
61142500024204245252
736420623515320110
oct3563634420610240
9565170734107055
10131103411343520
113885670a932090
1212854877240828
13581ccca028505
142453620747040
151025479792d65
hex773ce44310a0

131103411343520 has 192 divisors, whose sum is σ = 386259553677312. Its totient is φ = 40852775040000.

The previous prime is 131103411343511. The next prime is 131103411343537. The reversal of 131103411343520 is 25343114301131.

It is a super-2 number, since 2×1311034113435202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46062665 + ... + 48825975.

It is an arithmetic number, because the mean of its divisors is an integer number (2011768508736).

Almost surely, 2131103411343520 is an apocalyptic number.

131103411343520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131103411343520, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193129776838656).

131103411343520 is an abundant number, since it is smaller than the sum of its proper divisors (255156142333792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131103411343520 is a wasteful number, since it uses less digits than its factorization.

131103411343520 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2767195 (or 2767187 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 131103411343520 its reverse (25343114301131), we get a palindrome (156446525644651).

The spelling of 131103411343520 in words is "one hundred thirty-one trillion, one hundred three billion, four hundred eleven million, three hundred forty-three thousand, five hundred twenty".