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13110402241103 = 19965881418297
BaseRepresentation
bin1011111011001000000011…
…0111100101001001001111
31201102100020110210110201012
42332302000313211021033
53204300100433203403
643514500255435435
72522123663226416
oct276620067451117
951370213713635
1013110402241103
1141a50aa306572
121578a73225b7b
137413c85cc9bb
143347927d447d
1517b071c36ed8
hexbec80de524f

13110402241103 has 4 divisors (see below), whose sum is σ = 13176283659600. Its totient is φ = 13044520822608.

The previous prime is 13110402241033. The next prime is 13110402241201. The reversal of 13110402241103 is 30114220401131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13110402241103 - 212 = 13110402237007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110402244103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32940708950 + ... + 32940709347.

It is an arithmetic number, because the mean of its divisors is an integer number (3294070914900).

Almost surely, 213110402241103 is an apocalyptic number.

13110402241103 is a deficient number, since it is larger than the sum of its proper divisors (65881418497).

13110402241103 is an equidigital number, since it uses as much as digits as its factorization.

13110402241103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65881418496.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13110402241103 its reverse (30114220401131), we get a palindrome (43224622642234).

The spelling of 13110402241103 in words is "thirteen trillion, one hundred ten billion, four hundred two million, two hundred forty-one thousand, one hundred three".

Divisors: 1 199 65881418297 13110402241103