13110402241141 has 4 divisors (see below), whose sum is σ = 13110680351500. Its totient is φ = 13110124130784.

The previous prime is 13110402241033. The next prime is 13110402241201. The reversal of 13110402241141 is 14114220401131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 129362508900 + 12981039732241 = 359670^2 + 3602921^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110402241141 - 2¹¹ = 13110402239093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110402211141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138984456 + ... + 139078753.

It is an arithmetic number, because the mean of its divisors is an integer number (3277670087875).

Almost surely, 2^{13110402241141} is an apocalyptic number.

It is an amenable number.

13110402241141 is a deficient number, since it is larger than the sum of its proper divisors (278110359).

13110402241141 is an equidigital number, since it uses as much as digits as its factorization.

13110402241141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278110358.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 13110402241141 its reverse (14114220401131), we get a palindrome (27224622642272).

The spelling of 13110402241141 in words is "thirteen trillion, one hundred ten billion, four hundred two million, two hundred forty-one thousand, one hundred forty-one".