Base | Representation |
---|---|
bin | 10011000101000000000… |
… | …101110111010110010011 |
3 | 11122100000122122000212222 |
4 | 103011000011313112103 |
5 | 132440002304221111 |
6 | 2442141131411255 |
7 | 163501541501216 |
oct | 23050005672623 |
9 | 4570018560788 |
10 | 1311040304531 |
11 | 466011089411 |
12 | 1921088b3b2b |
13 | 96827494109 |
14 | 4765194b77d |
15 | 241832c67db |
hex | 13140177593 |
1311040304531 has 2 divisors, whose sum is σ = 1311040304532. Its totient is φ = 1311040304530.
The previous prime is 1311040304479. The next prime is 1311040304597. The reversal of 1311040304531 is 1354030401131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311040304531 - 26 = 1311040304467 is a prime.
It is a super-2 number, since 2×13110403045312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1311040304531.
It is not a weakly prime, because it can be changed into another prime (1311040304831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655520152265 + 655520152266.
It is an arithmetic number, because the mean of its divisors is an integer number (655520152266).
Almost surely, 21311040304531 is an apocalyptic number.
1311040304531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311040304531 is an equidigital number, since it uses as much as digits as its factorization.
1311040304531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 1311040304531 its reverse (1354030401131), we get a palindrome (2665070705662).
The spelling of 1311040304531 in words is "one trillion, three hundred eleven billion, forty million, three hundred four thousand, five hundred thirty-one".
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