Base | Representation |
---|---|
bin | 1011111011001000000101… |
… | …1101100101010001101011 |
3 | 1201102100021011112121000121 |
4 | 2332302001131211101223 |
5 | 3204300111010444430 |
6 | 43514501253144111 |
7 | 2522124144010243 |
oct | 276620135452153 |
9 | 51370234477017 |
10 | 13110412203115 |
11 | 41a51049a0137 |
12 | 1578a7662b037 |
13 | 7413ca6aa196 |
14 | 334793c68b23 |
15 | 17b072a53a7a |
hex | bec8176546b |
13110412203115 has 32 divisors (see below), whose sum is σ = 16006082795136. Its totient is φ = 10306280540160.
The previous prime is 13110412203061. The next prime is 13110412203179. The reversal of 13110412203115 is 51130221401131.
It is not a de Polignac number, because 13110412203115 - 221 = 13110410105963 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13110412203115.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2095316067 + ... + 2095322323.
It is an arithmetic number, because the mean of its divisors is an integer number (500190087348).
Almost surely, 213110412203115 is an apocalyptic number.
13110412203115 is a deficient number, since it is larger than the sum of its proper divisors (2895670592021).
13110412203115 is a wasteful number, since it uses less digits than its factorization.
13110412203115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11959.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13110412203115 its reverse (51130221401131), we get a palindrome (64240633604246).
The spelling of 13110412203115 in words is "thirteen trillion, one hundred ten billion, four hundred twelve million, two hundred three thousand, one hundred fifteen".
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