Base | Representation |
---|---|
bin | 1011111011001000001000… |
… | …1011110011100000001011 |
3 | 1201102100022000100012021112 |
4 | 2332302002023303200023 |
5 | 3204300122111220021 |
6 | 43514502405000535 |
7 | 2522124352004414 |
oct | 276620213634013 |
9 | 51370260305245 |
10 | 13110424320011 |
11 | 41a51108167a7 |
12 | 1578a7a6b314b |
13 | 741400060445 |
14 | 33479570080b |
15 | 17b073b48d5b |
hex | bec822f380b |
13110424320011 has 2 divisors, whose sum is σ = 13110424320012. Its totient is φ = 13110424320010.
The previous prime is 13110424319983. The next prime is 13110424320017. The reversal of 13110424320011 is 11002342401131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110424320011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110424320017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555212160005 + 6555212160006.
It is an arithmetic number, because the mean of its divisors is an integer number (6555212160006).
Almost surely, 213110424320011 is an apocalyptic number.
13110424320011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110424320011 is an equidigital number, since it uses as much as digits as its factorization.
13110424320011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13110424320011 its reverse (11002342401131), we get a palindrome (24112766721142).
The spelling of 13110424320011 in words is "thirteen trillion, one hundred ten billion, four hundred twenty-four million, three hundred twenty thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •