13110441240451 has 2 divisors, whose sum is σ = 13110441240452. Its totient is φ = 13110441240450.

The previous prime is 13110441240359. The next prime is 13110441240529. The reversal of 13110441240451 is 15404214401131.

13110441240451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15404214401131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13110441240451 - 2⁹ = 13110441239939 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110441240151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555220620225 + 6555220620226.

It is an arithmetic number, because the mean of its divisors is an integer number (6555220620226).

Almost surely, 2^{13110441240451} is an apocalyptic number.

13110441240451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110441240451 is an equidigital number, since it uses as much as digits as its factorization.

13110441240451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 13110441240451 its reverse (15404214401131), we get a palindrome (28514655641582).

The spelling of 13110441240451 in words is "thirteen trillion, one hundred ten billion, four hundred forty-one million, two hundred forty thousand, four hundred fifty-one".