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131104424013 = 343701474671
BaseRepresentation
bin111101000011001101…
…1101100000001001101
3110112101220002210112220
41322012123230001031
54122000213032023
6140121210445553
712320614134303
oct1720633540115
9415356083486
10131104424013
1150668036252
12214aa7338b9
13c494944074
1464ba03a273
153624cc03e3
hex1e866ec04d

131104424013 has 4 divisors (see below), whose sum is σ = 174805898688. Its totient is φ = 87402949340.

The previous prime is 131104423937. The next prime is 131104424041. The reversal of 131104424013 is 310424401131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131104424013 - 210 = 131104422989 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131104424513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21850737333 + ... + 21850737338.

It is an arithmetic number, because the mean of its divisors is an integer number (43701474672).

Almost surely, 2131104424013 is an apocalyptic number.

It is an amenable number.

131104424013 is a deficient number, since it is larger than the sum of its proper divisors (43701474675).

131104424013 is an equidigital number, since it uses as much as digits as its factorization.

131104424013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43701474674.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131104424013 its reverse (310424401131), we get a palindrome (441528825144).

The spelling of 131104424013 in words is "one hundred thirty-one billion, one hundred four million, four hundred twenty-four thousand, thirteen".

Divisors: 1 3 43701474671 131104424013