Base | Representation |
---|---|
bin | 111101000011010001… |
… | …1101111001001000001 |
3 | 110112102001001222211211 |
4 | 1322012203233021001 |
5 | 4122001233041303 |
6 | 140121324010121 |
7 | 12320641102603 |
oct | 1720643571101 |
9 | 415361058754 |
10 | 131106533953 |
11 | 506692474aa |
12 | 214ab390941 |
13 | c495202555 |
14 | 64ba429173 |
15 | 362508a66d |
hex | 1e868ef241 |
131106533953 has 2 divisors, whose sum is σ = 131106533954. Its totient is φ = 131106533952.
The previous prime is 131106533939. The next prime is 131106533963. The reversal of 131106533953 is 359335601131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91063322289 + 40043211664 = 301767^2 + 200108^2 .
It is a cyclic number.
It is not a de Polignac number, because 131106533953 - 217 = 131106402881 is a prime.
It is not a weakly prime, because it can be changed into another prime (131106533903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65553266976 + 65553266977.
It is an arithmetic number, because the mean of its divisors is an integer number (65553266977).
Almost surely, 2131106533953 is an apocalyptic number.
It is an amenable number.
131106533953 is a deficient number, since it is larger than the sum of its proper divisors (1).
131106533953 is an equidigital number, since it uses as much as digits as its factorization.
131106533953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109350, while the sum is 40.
The spelling of 131106533953 in words is "one hundred thirty-one billion, one hundred six million, five hundred thirty-three thousand, nine hundred fifty-three".
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