Base | Representation |
---|---|
bin | 111101000011010100… |
… | …1010111001111100011 |
3 | 110112102010211221010122 |
4 | 1322012221113033203 |
5 | 4122002122241211 |
6 | 140121415350455 |
7 | 12320656455044 |
oct | 1720651271743 |
9 | 415363757118 |
10 | 131108008931 |
11 | 5066a064699 |
12 | 214ab98242b |
13 | c4955caa13 |
14 | 64ba6d08cb |
15 | 362527c6db |
hex | 1e86a573e3 |
131108008931 has 2 divisors, whose sum is σ = 131108008932. Its totient is φ = 131108008930.
The previous prime is 131108008921. The next prime is 131108008951. The reversal of 131108008931 is 139800801131.
It is a weak prime.
It is an emirp because it is prime and its reverse (139800801131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131108008931 - 210 = 131108007907 is a prime.
It is a super-2 number, since 2×1311080089312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131108008891 and 131108008900.
It is not a weakly prime, because it can be changed into another prime (131108008921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65554004465 + 65554004466.
It is an arithmetic number, because the mean of its divisors is an integer number (65554004466).
Almost surely, 2131108008931 is an apocalyptic number.
131108008931 is a deficient number, since it is larger than the sum of its proper divisors (1).
131108008931 is an equidigital number, since it uses as much as digits as its factorization.
131108008931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 131108008931 in words is "one hundred thirty-one billion, one hundred eight million, eight thousand, nine hundred thirty-one".
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