1311101000414 has 4 divisors (see below), whose sum is σ = 1966651500624. Its totient is φ = 655550500206.

The previous prime is 1311101000413. The next prime is 1311101000431. The reversal of 1311101000414 is 4140001011131.

It is a semiprime because it is the product of two primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1311101000392 and 1311101000401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311101000413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327775250102 + ... + 327775250105.

It is an arithmetic number, because the mean of its divisors is an integer number (491662875156).

Almost surely, 2^{1311101000414} is an apocalyptic number.

1311101000414 is a deficient number, since it is larger than the sum of its proper divisors (655550500210).

1311101000414 is an equidigital number, since it uses as much as digits as its factorization.

1311101000414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655550500209.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1311101000414 its reverse (4140001011131), we get a palindrome (5451102011545).

The spelling of 1311101000414 in words is "one trillion, three hundred eleven billion, one hundred one million, four hundred fourteen", and thus it is an aban number.