Base | Representation |
---|---|
bin | 111101000011011000… |
… | …1010101110100011001 |
3 | 110112102021210011212212 |
4 | 1322012301111310121 |
5 | 4122003141201444 |
6 | 140121532244505 |
7 | 12321013315142 |
oct | 1720661256431 |
9 | 415367704785 |
10 | 131110100249 |
11 | 50670262957 |
12 | 214b0610735 |
13 | c495b8089b |
14 | 64baab6ac9 |
15 | 362554219e |
hex | 1e86c55d19 |
131110100249 has 2 divisors, whose sum is σ = 131110100250. Its totient is φ = 131110100248.
The previous prime is 131110100239. The next prime is 131110100273. The reversal of 131110100249 is 942001011131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125968206400 + 5141893849 = 354920^2 + 71707^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131110100249 is a prime.
It is not a weakly prime, because it can be changed into another prime (131110100239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050124 + 65555050125.
It is an arithmetic number, because the mean of its divisors is an integer number (65555050125).
Almost surely, 2131110100249 is an apocalyptic number.
It is an amenable number.
131110100249 is a deficient number, since it is larger than the sum of its proper divisors (1).
131110100249 is an equidigital number, since it uses as much as digits as its factorization.
131110100249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 131110100249 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, two hundred forty-nine".
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