Base | Representation |
---|---|
bin | 111101000011011000… |
… | …1010101110111011001 |
3 | 110112102021210012010222 |
4 | 1322012301111313121 |
5 | 4122003141203231 |
6 | 140121532245425 |
7 | 12321013315535 |
oct | 1720661256731 |
9 | 415367705128 |
10 | 131110100441 |
11 | 50670263011 |
12 | 214b0610875 |
13 | c495b809b8 |
14 | 64baab6bc5 |
15 | 362554227b |
hex | 1e86c55dd9 |
131110100441 has 2 divisors, whose sum is σ = 131110100442. Its totient is φ = 131110100440.
The previous prime is 131110100413. The next prime is 131110100453. The reversal of 131110100441 is 144001011131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129891043216 + 1219057225 = 360404^2 + 34915^2 .
It is an emirp because it is prime and its reverse (144001011131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131110100441 - 26 = 131110100377 is a prime.
It is not a weakly prime, because it can be changed into another prime (131110100411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050220 + 65555050221.
It is an arithmetic number, because the mean of its divisors is an integer number (65555050221).
Almost surely, 2131110100441 is an apocalyptic number.
It is an amenable number.
131110100441 is a deficient number, since it is larger than the sum of its proper divisors (1).
131110100441 is an equidigital number, since it uses as much as digits as its factorization.
131110100441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 131110100441 its reverse (144001011131), we get a palindrome (275111111572).
The spelling of 131110100441 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, four hundred forty-one".
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