131110100497 has 2 divisors, whose sum is σ = 131110100498. Its totient is φ = 131110100496.

The previous prime is 131110100483. The next prime is 131110100549. The reversal of 131110100497 is 794001011131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129225151441 + 1884949056 = 359479^2 + 43416^2 .

It is an emirp because it is prime and its reverse (794001011131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131110100497 is a prime.

It is not a weakly prime, because it can be changed into another prime (131110100897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050248 + 65555050249.

It is an arithmetic number, because the mean of its divisors is an integer number (65555050249).

Almost surely, 2^131110100497 is an apocalyptic number.

It is an amenable number.

131110100497 is a deficient number, since it is larger than the sum of its proper divisors (1).

131110100497 is an equidigital number, since it uses as much as digits as its factorization.

131110100497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 28.

The spelling of 131110100497 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, four hundred ninety-seven".