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131110100550 = 2335211213292129
BaseRepresentation
bin111101000011011000…
…1010101111001000110
3110112102021210012022000
41322012301111321012
54122003141204200
6140121532250130
712321013316052
oct1720661257106
9415367705260
10131110100550
1150670263100
12214b0610946
13c495b80a70
1464baab6c62
153625542300
hex1e86c55e46

131110100550 has 576 divisors, whose sum is σ = 442612296000. Its totient is φ = 28314316800.

The previous prime is 131110100549. The next prime is 131110100567. The reversal of 131110100550 is 55001011131.

131110100550 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 10 + 100 + 550 = 666.

It is a super-2 number, since 2×1311101005502 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 61581886 + ... + 61584014.

It is an arithmetic number, because the mean of its divisors is an integer number (768424125).

Almost surely, 2131110100550 is an apocalyptic number.

131110100550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 131110100550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221306148000).

131110100550 is an abundant number, since it is smaller than the sum of its proper divisors (311502195450).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131110100550 is a wasteful number, since it uses less digits than its factorization.

131110100550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2214 (or 2192 counting only the distinct ones).

The product of its (nonzero) digits is 75, while the sum is 18.

Adding to 131110100550 its reverse (55001011131), we get a palindrome (186111111681).

The spelling of 131110100550 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, five hundred fifty".