131110101307 has 2 divisors, whose sum is σ = 131110101308. Its totient is φ = 131110101306.

The previous prime is 131110101277. The next prime is 131110101329. The reversal of 131110101307 is 703101011131.

It is a strong prime.

It is an emirp because it is prime and its reverse (703101011131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131110101307 - 2²³ = 131101712699 is a prime.

It is not a weakly prime, because it can be changed into another prime (131110101337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050653 + 65555050654.

It is an arithmetic number, because the mean of its divisors is an integer number (65555050654).

Almost surely, 2^131110101307 is an apocalyptic number.

131110101307 is a deficient number, since it is larger than the sum of its proper divisors (1).

131110101307 is an equidigital number, since it uses as much as digits as its factorization.

131110101307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 19.

Adding to 131110101307 its reverse (703101011131), we get a palindrome (834211112438).

The spelling of 131110101307 in words is "one hundred thirty-one billion, one hundred ten million, one hundred one thousand, three hundred seven".