Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101111000000000000011 |
3 | 11122100011220002000100112 |
4 | 103011003231320000003 |
5 | 132440113341441421 |
6 | 2442151143141535 |
7 | 163503210452225 |
oct | 23050355700003 |
9 | 4570156060315 |
10 | 1311101124611 |
11 | 46604244a443 |
12 | 1921251448ab |
13 | 96836c6a425 |
14 | 47659a60415 |
15 | 241887dc45b |
hex | 13143b78003 |
1311101124611 has 2 divisors, whose sum is σ = 1311101124612. Its totient is φ = 1311101124610.
The previous prime is 1311101124563. The next prime is 1311101124689. The reversal of 1311101124611 is 1164211011131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311101124611 is a prime.
It is a super-3 number, since 3×13111011246113 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1311101124511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550562305 + 655550562306.
It is an arithmetic number, because the mean of its divisors is an integer number (655550562306).
Almost surely, 21311101124611 is an apocalyptic number.
1311101124611 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311101124611 is an equidigital number, since it uses as much as digits as its factorization.
1311101124611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 23.
Adding to 1311101124611 its reverse (1164211011131), we get a palindrome (2475312135742).
The spelling of 1311101124611 in words is "one trillion, three hundred eleven billion, one hundred one million, one hundred twenty-four thousand, six hundred eleven".
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